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A114573
Numbers k such that phi(k) is a perfect 11th power.
1
1, 2, 3855, 4096, 4112, 4352, 5120, 5140, 5440, 6144, 6168, 6528, 7680, 7710, 8160, 5570645, 8388608, 8388736, 8421376, 8912896, 8913032, 8947712, 10485760, 10485920, 10526720, 11141120, 11141290, 11184640, 12582912, 12583104
OFFSET
1,2
COMMENTS
Given the fact that phi(n) > sqrt(n) for all n except n=2 and n=6 we can see that every 11th power does appear as value only a finite number of times. What bounds on the density of this sequence can be proved?
LINKS
EXAMPLE
phi(4096) = 2048 = 2^11.
MATHEMATICA
For[n = 1, n < 100000, n++, If[EulerPhi[n]^(1/11) == Floor[EulerPhi[n]^(1/11)], Print[n]]]
CROSSREFS
Cf. A039770 (square), A039771 (cube), A078164 (4th), A078165 (5th), A078166 (6th), A078167 (7th), A078168 (8th), A078169 (9th), A078170 (10th power), A000010.
Sequence in context: A094211 A372116 A350418 * A285086 A367436 A024035
KEYWORD
nonn
AUTHOR
EXTENSIONS
More terms from Stefan Steinerberger, May 16 2007
STATUS
approved