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A114561
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a(0) = 0; thereafter a(n+1) = 4^a(n).
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9
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0, 1, 4, 256, 13407807929942597099574024998205846127479365820592393377723561443721764030073546976801874298166903427690031858186486050853753882811946569946433649006084096
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OFFSET
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0,3
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COMMENTS
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Or, define two sequences by q(0) = 0, p(n) = 2^q(n), q(n+1) = p(n)^2; sequence gives q(n).
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LINKS
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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