|
| |
|
|
A114118
|
|
Number triangle T(n,k)=sum{j=0..n, C(floor((n+k+j)/3),k)C(k,floor((n+k+j)/3))}.
|
|
1
| |
|
|
1, 2, 1, 1, 3, 1, 0, 2, 3, 1, 0, 1, 3, 3, 1, 0, 0, 2, 3, 3, 1, 0, 0, 1, 3, 3, 3, 1, 0, 0, 0, 2, 3, 3, 3, 1, 0, 0, 0, 1, 3, 3, 3, 3, 1, 0, 0, 0, 0, 2, 3, 3, 3, 3, 1, 0, 0, 0, 0, 1, 3, 3, 3, 3, 3, 1, 0, 0, 0, 0, 0, 2, 3, 3, 3, 3, 3, 1, 0, 0, 0, 0, 0, 1, 3, 3, 3, 3, 3, 3, 1, 0, 0, 0, 0, 0, 0, 2, 3, 3, 3, 3, 3, 3, 1
(list; table; graph; refs; listen; history; internal format)
|
|
|
|
OFFSET
| 0,2
|
|
|
COMMENTS
| Row sums are A114119. Diagonal sums are A008619(n+1).
|
|
|
EXAMPLE
| Triangle begins
1...........................= 1 = 1 mod 3
2,1.........................= 3 = 0 mod 3
1,3,1.......................= 5 = 2 mod 3
0,2,3,1.....................= 6 = 0 mod 3
0,1,3,3,1...................= 8 = 2 mod 3
0,0,2,3,3,1.................= 9 = 0 mod 3
0,0,1,3,3,3,1...............= 11 = 2 mod 3
0,0,0,2,3,3,3,1.............= 12 = 0 mod 3
0,0,0,1,3,3,3,3,1...........= 14 = 2 mod 3
0,0,0,0,2,3,3,3,3,1.........= 15 = 0 mod 3
0,0,0,0,1,3,3,3,3,3,1.......= 17 = 2 mod 3
0,0,0,0,0,2,3,3,3,3,3,1.....= 18 = 0 mod 3
|
|
|
CROSSREFS
| Sequence in context: A103910 A155993 A147867 * A146014 A202241 A106177
Adjacent sequences: A114115 A114116 A114117 * A114119 A114120 A114121
|
|
|
KEYWORD
| easy,nonn,tabl
|
|
|
AUTHOR
| Paul Barry (pbarry(AT)wit.ie), Nov 13 2005
|
| |
|
|