%I #2 Mar 30 2012 17:27:48
%S 1,2,4,3,6,8,12,10,5,14,22,16,24,20,26,9,28,18,30,42,32,34,36,44,7,38,
%T 40,138,144,46,146,140,142,148,150,45,152,154,156,48,158,50,160,236,
%U 238,162,164,52,11,240,166,242,168,54,170,56,172,174,176,66,178,180,244,17
%N Where n appears in A111390.
%C Inverse of permutation A111390.
%e A111390(20) = 14, hence a(14) = 20.
%Y Cf. A111390.
%K nonn
%O 1,2
%A _Klaus Brockhaus_, Nov 13 2005, Jan 01 2006
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