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Rearrangement of Fibonacci numbers so that the n-th partial concatenation is a multiple of the n-th Fibonacci number.
1

%I #7 Dec 06 2015 23:01:26

%S 1,1,2,5,55,144,13,28657,46368

%N Rearrangement of Fibonacci numbers so that the n-th partial concatenation is a multiple of the n-th Fibonacci number.

%C The next term should be +-1 modulo 11 and 0 modulo 5, which is impossible.

%C Triangular numbers cannot be so arranged.

%Y Cf. A114030.

%K base,nonn,full,fini

%O 1,3

%A _Amarnath Murthy_, Nov 13 2005

%E Completed by _Max Alekseyev_, May 02 2009