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A113613 Beginning with 7, distinct primes such that every partial concatenation is a palindrome. 2
7, 17, 5717, 27175717, 212717571727175717, 8717571727175717212717571727175717, 2327175717271757172127175717271757178717571727175717212717571727175717 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
From Michael S. Branicky, Aug 09 2022: (Start)
If terms were not required to be distinct, then 7, 7, 7, ... or 7, 17, 17, 17, ... satisfy the requirement.
a(11) has 1132 digits. (End)
LINKS
Michael S. Branicky, Table of n, a(n) for n = 1..10
EXAMPLE
7, 717, 7175717, 717571727175717, ... are all palindromes.
PROG
(Python)
from sympy import isprime
from itertools import count, islice, product
def pals(digs):
yield from digs
for d in count(2):
for p in product(digs, repeat=d//2):
left = "".join(p)
for mid in [[""], digs][d%2]:
yield left + mid + left[::-1]
def folds(s): # generator of suffixes of palindromes starting with s
for i in range((len(s)+1)//2, len(s)+1):
for mid in [True, False]:
t = s[:i] + (s[:i-1][::-1] if mid else s[:i][::-1])
if t.startswith(s):
yield t[len(s):]
yield from ("".join(p)+s[::-1] for p in pals("0123456789"))
def agen():
s, seen = "7", {"7"}; yield 7
while True:
for t in folds(s):
if len(t) and t[0] != "0" and t not in seen and isprime(int(t)):
break
s += t; seen.add(t); yield int(t)
print(list(islice(agen(), 7))) # Michael S. Branicky, Aug 09 2022
CROSSREFS
Cf. A113612.
Sequence in context: A177366 A138491 A022511 * A070415 A034083 A185455
KEYWORD
base,nonn
AUTHOR
Amarnath Murthy, Nov 09 2005
EXTENSIONS
Name clarified and a(5) and beyond from Michael S. Branicky, Aug 09 2022
STATUS
approved

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Last modified April 24 20:08 EDT 2024. Contains 371963 sequences. (Running on oeis4.)