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A113504
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a(0) = 1. For n >= 1, a(n) = number of earlier terms of the sequence that have the same number of ones in their binary representations as n.
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4
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1, 1, 2, 0, 3, 1, 1, 0, 5, 2, 2, 0, 2, 0, 0, 0, 8, 2, 2, 0, 2, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 13, 2, 2, 1, 2, 1, 1, 0, 2, 1, 1, 0, 1, 0, 0, 0, 2, 1, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 28, 2, 2, 2, 2, 2, 2, 0, 2, 2, 2, 0, 2, 0, 0, 0, 2, 2, 2, 0, 2, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 2, 2, 2, 0, 2, 0, 0, 0, 2
(list; graph; refs; listen; history; internal format)
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OFFSET
| 0,3
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COMMENTS
| A115211(n) = A00120(a(n)) = number of ones in binary representation of a(n) for n>0; record values: A115212(n) = a(A115213(n)). - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Jan 17 2006
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EXAMPLE
| The first 8 terms (terms 0 through 7) written in binary are [1,1,10,0,11,1,1,0]. Term 8 gives the number of earlier terms with the same number of 1's in their binary representation as 8 (which is 1000 in binary, for one 1). a(8) = 5 because there are five terms among the earlier terms with one binary 1 (terms with one 1: 1, 1, 2, 1 and 1).
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CROSSREFS
| Cf. A113503, A000120.
Sequence in context: A170942 A002187 A124756 * A124754 A047983 A070812
Adjacent sequences: A113501 A113502 A113503 * A113505 A113506 A113507
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KEYWORD
| nonn
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AUTHOR
| Leroy Quet, Jan 10 2006
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EXTENSIONS
| More terms from Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Jan 17 2006
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