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A112999 Cumulative sum of n factorial to n-th power. 0
1, 5, 221, 331997, 24883531997, 139314094387531997, 82606411393217618227531997, 6984964247224120535022357995827531997, 109110688415578301444592123476429107940843827531997 (list; graph; refs; listen; history; internal format)
OFFSET

1,2

COMMENTS

a(2) is prime. a(4) is prime, as pointed out by Poo Sung on Prime Curios for 331997. a(3), a(5) and a(11) are semiprime. a(6), a(7), a(8) and a(10) have 3 prime factors. a(9) has 7 prime factors. a(12) has at least 4 prime factors. From a(4) onwards, all terms are congruent to 31997 mod 10^5. From a(5) onwards, all terms are congruent to 531997 mod 10^6. From a(5) onwards, all terms are congruent to 7531997 mod 10^7. The number of digits of a(n) for n = 1, 2, 3, ..., 12 are 1, 1, 3, 6, 11, 18, 26, 37, 51, 84, 105.

FORMULA

a(n) = SUM[from k = 1 to n] (k!)^k. a(n) = SUM[from k = 1 to n] (A000142(k))^k. a(n) = SUM[from k = 1 to n] A036740(k). a(n) = SUM[from k = 1 to n] A002109(k) * A000178(k-1)

EXAMPLE

a(1) = (1!)^1 = 1^1 = 1.

a(2) = (1!)^1 + (2!)^2 = 1^1 + 2^2 = 1 + 4 = 5.

a(3) = (1!)^1 + (2!)^2 + (3!)^3 = 1^1 + 2^2 + 6^3 = 1 + 4 + 216 = 221.

a(4) = (1!)^1 + (2!)^2 + (3!)^3 + (4!)^4 = 1^1 + 2^2 + 6^3 + 24^4 = 1 + 4 + 216 + 331776 = 331997.

a(10) = (1!)^1 + (2!)^2 + (3!)^3 + (4!)^4 + (5!)^5 + (6!)^6 + (7!)^7 + (8!)^8 + (9!)^9 + (10!)^10.

CROSSREFS

Cf. A000142, A000178, A002109, A036740.

Sequence in context: A066462 A046193 A195633 * A185551 A200988 A201491

Adjacent sequences:  A112996 A112997 A112998 * A113000 A113001 A113002

KEYWORD

easy,nonn

AUTHOR

Jonathan Vos Post (jvospost3(AT)gmail.com), Jan 03 2006

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Last modified February 15 23:53 EST 2012. Contains 205860 sequences.