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%I #9 Apr 09 2014 10:16:58
%S 1,2,4,2,4,6,8,2,6,10,8,4,8,4,10,4,6,12,12,4,12,8,6,4,12,6,4,5,8,6,12,
%T 2,9,14,16,12,12,8,16,8,10,8,12,4,16,12,6,4,14,7,13,12,12,2,11,26,20,
%U 8,6,8,16,4,14,6,10,32,16,4,12,16,12,6,15,6,24,12,12,14,12,4
%N a(n) = sum of terms in n-th row of array A112790.
%C Number of terms in row n of array A112790 is A000005(n).
%e The irregular array A112790's 5th row is [3,1]. So a(5) = 3+1 = 4.
%Y Cf. A000005, A112790.
%K nonn
%O 1,2
%A _Leroy Quet_, Dec 31 2005
%E More terms from _R. J. Mathar_, Aug 29 2007
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