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Next term is the sum of the last 10 digits in the sequence, beginning with a(10) = 5.
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%I #3 Mar 31 2012 10:30:58

%S 0,0,0,0,0,0,0,0,0,5,5,10,11,13,17,25,22,25,30,29,32,30,29,33,36,34,

%T 36,42,37,41,37,40,35,37,37,42,38,45,46,46,46,50,44,43,40,34,31,30,25,

%U 25,28,31,31,32,30,26,24,26,30,28,35,35,37,39,48,50,47,50,45,42,36,40,33

%N Next term is the sum of the last 10 digits in the sequence, beginning with a(10) = 5.

%C Variation on Angelini's A112395. The sequence cycles at a(28)=42 and the loop has 312 terms. Computed by Gilles Sadowski.

%e a(28)=42 because 2+9 + 3+3 + 3+6 + 3+4 + 3+6 = 42

%Y Cf. A112395, A004207, A065075, A001370.

%K base,easy,nonn

%O 1,10

%A _Alexandre Wajnberg_, Dec 11 2005