|
| |
|
|
A112105
|
|
G.f. A(x) satisfies A(A(x)) = B(x) such that the coefficients of B(x) consist of all 1's and 2's, with A(0) = 0.
|
|
3
| |
|
|
1, 1, 0, 0, 1, -3, 7, -10, -5, 84, -248, 90, 2160, -7541, -5846, 122824, -186259, -2036532, 8665409, 36714511, -345711246, -517802065, 14415153844, -9423161197, -653074772917, 1896978939457, 32374651932128, -184814895196023, -1733326272860598, 16839263882542991, 96742403684106435
(list; graph; refs; listen; history; internal format)
|
|
|
|
OFFSET
| 1,6
|
|
|
EXAMPLE
| A(x) = x + x^2 + x^5 - 3*x^6 + 7*x^7 - 10*x^8 - 5*x^9 +...
where A(A(x)) = x + 2*x^2 + 2*x^3 + x^4 + 2*x^5 + x^6 +... is the g.f. of A112104.
|
|
|
PROG
| (PARI) {a(n, m=2)=local(F=x+x^2+x*O(x^n), G); if(n<1, 0, for(k=3, n, G=F+x*O(x^k); for(i=1, m-1, G=subst(F, x, G)); F=F-((polcoeff(G, k)-1)\m)*x^k); return(polcoeff(F, n, x)))}
|
|
|
CROSSREFS
| Cf. A112104, A112106-A112127.
Sequence in context: A118559 A189244 A127789 * A065501 A144385 A144399
Adjacent sequences: A112102 A112103 A112104 * A112106 A112107 A112108
|
|
|
KEYWORD
| sign
|
|
|
AUTHOR
| Paul D. Hanna (pauldhanna(AT)juno.com), Aug 27 2005
|
| |
|
|
