OFFSET
1,5
COMMENTS
Let M = the infinite lower triangular matrix of Stirling cycle numbers (A008275). Perform M^n * [1, 0, 0, 0, ...] forming an array. Antidiagonals of that array become the rows of this triangle.
LINKS
Seiichi Manyama, Antidiagonals n = 1..140, flattened
EXAMPLE
Row 5 of the triangle = 1, 4, 15, 35, 24; generated from M^n * [1,0,0,0,...] (n = 1 through 5); then take antidiagonals.
Terms in the array, first few rows are:
1, 1, 2, 6, 24, 120, ...
1, 2, 7, 35, 228, 1834, ...
1, 3, 15, 105, 947, 10472, ...
1, 4, 26, 234, 2697, 37919, ...
1, 5, 40, 440, 6170, 105315, ...
1, 6, 57, 741, 12244, 245755, ...
...
First few rows of the triangle are:
1;
1, 1;
1, 2, 2;
1, 3, 7, 6;
1, 4, 15, 35, 24;
1, 5, 26, 105, 228, 120;
1, 6, 40, 234, 947, 1834, 720;
...
KEYWORD
nonn,tabl
AUTHOR
Gary W. Adamson, Aug 21 2005
EXTENSIONS
a(28), a(36) and a(45) corrected by Seiichi Manyama, Feb 11 2022
STATUS
approved