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A111569
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a(n) = a(n-1) + a(n-3) + a(n-4) for n>3, a(0) = -1, a(1) = 1, a(2) = 2, a(3) = 1.
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6
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-1, 1, 2, 1, 1, 4, 7, 9, 14, 25, 41, 64, 103, 169, 274, 441, 713, 1156, 1871, 3025, 4894, 7921, 12817, 20736, 33551, 54289, 87842, 142129, 229969, 372100, 602071, 974169, 1576238, 2550409, 4126649, 6677056, 10803703, 17480761, 28284466, 45765225
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OFFSET
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0,3
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COMMENTS
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In reference to the program code given, 4*tesseq[A*H] = A001638 (a Fielder sequence) where A001638(2n) = L(n)^2. Here we have: a(2n+1) = A007598(n+1) = Fibonacci(n+1)^2.
First bisection is A260259 (see previous comment for the second bisection). [Bruno Berselli, Nov 02 2015]
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REFERENCES
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Daniel C. Fielder, Special integer sequences controlled by three parameters. Fibonacci Quart 6, 1968, 64-70.
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LINKS
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Table of n, a(n) for n=0..39.
Robert Munafo, Sequences Related to Floretions
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FORMULA
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G.f. (1-2*x-x^2)/((x^2+x-1)*(1+x^2)).
a(n) = 2*A056594(n+3)/5-6*A056594(n)/5+A000032(n+1)/5. [R. J. Mathar, Nov 12 2009]
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PROG
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Floretion Algebra Multiplication Program, FAMP Code: 4kbaseiseq[B+H] with B = - .25'i + .25'j - .25i' + .25j' + k' - .5'kk' - .25'ik' - .25'jk' - .25'ki' - .25'kj' - .5e and H = + .75'ii' + .75'jj' + .75'kk' + .75e
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CROSSREFS
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Cf. A000045, A001638, A007598, A111570, A111571, A111572, A111573, A260259.
Sequence in context: A011016 A096540 A277081 * A213786 A055130 A051292
Adjacent sequences: A111566 A111567 A111568 * A111570 A111571 A111572
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KEYWORD
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easy,sign
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AUTHOR
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Creighton Dement, Aug 07 2005
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STATUS
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approved
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