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f(f(n+1))-f(f(n)), where f(m) = 3^m.
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%I #7 Feb 14 2018 21:03:31

%S 24,19656,7625597465304,443426488243037769948249622993552407816,

%T 87189642485960958202911070585860771696964072404731750085525219437990967093722996516987306869061734867160436075772824

%N f(f(n+1))-f(f(n)), where f(m) = 3^m.

%p f:=n->3^n; g:=n->f(f(n+1))-f(f(n)); [seq(g(n),n=0..4)]; # _N. J. A. Sloane_, Feb 14 2018

%K nonn

%O 0,1

%A _N. J. A. Sloane_, Nov 12 2005