OFFSET
1,2
COMMENTS
The last term of each continued fraction is considered to be >= 2, for n >= 2.
EXAMPLE
1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 = 49/20 = 2 + 1/(2 + 1/(4 + 1/2)), so the 6th term of the sequence is 2*2*4*2 = 32.
PROG
(PARI) for(n=1, 30, v=contfrac(sum(k=1, n, 1/k)); print1(prod(j=1, length(v), v[j]), ", "))
CROSSREFS
KEYWORD
nonn
AUTHOR
Leroy Quet, Oct 06 2005
EXTENSIONS
More terms from Klaus Brockhaus, Oct 08 2005
STATUS
approved