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A110925
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a(1) = 1; for n>1, a(n) is the smallest positive integer such that the continued fraction [a(1),a(2),a(3),...,a(n)] has numerator divisible by n.
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0
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1, 1, 1, 2, 4, 2, 7, 2, 7, 10, 5, 10, 4, 2, 7, 2, 9
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,4
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EXAMPLE
| a(5) = 4 because 4 is the smallest positive integer m such that the continued fraction [1,1,1,2,m] has numerator divisible by 5.
1 + 1/(1 + 1/(1 + 1/(2 + 1/4))) = 35/22 and 35 is divisible by 5.
[1,1,1,2,4,2,7,2,7,10,5,10] equals 4878960/3065089 and 12 divides 4878960.
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CROSSREFS
| Sequence in context: A177847 A021416 A094756 * A073017 A171977 A059866
Adjacent sequences: A110922 A110923 A110924 * A110926 A110927 A110928
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KEYWORD
| nonn,fini,full
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AUTHOR
| Leroy Quet Sep 23 2005
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EXTENSIONS
| Completed by Hans Havermann (gladhobo(AT)teksavvy.com), Sep 23 2005. Rechecked Oct 23, 2005
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