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A110925
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a(1) = 1; for n>1, a(n) is the smallest positive integer such that the continued fraction [a(1),a(2),a(3),...,a(n)] has numerator divisible by n.
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0
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1, 1, 1, 2, 4, 2, 7, 2, 7, 10, 5, 10, 4, 2, 7, 2, 9
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OFFSET
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1,4
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LINKS
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EXAMPLE
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a(5) = 4 because 4 is the smallest positive integer m such that the continued fraction [1,1,1,2,m] has numerator divisible by 5.
1 + 1/(1 + 1/(1 + 1/(2 + 1/4))) = 35/22 and 35 is divisible by 5.
[1,1,1,2,4,2,7,2,7,10,5,10] equals 4878960/3065089 and 12 divides 4878960.
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CROSSREFS
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KEYWORD
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nonn,fini,full
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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