OFFSET
1,1
COMMENTS
These numbers need to be of the form 4*j then (16*j^2-8)/8 = 2*j^2-1.
A066436 gives resulting primes p such that 8p+8 is square. - Ray Chandler, Sep 15 2005
LINKS
G. C. Greubel, Table of n, a(n) for n = 1..5000
FORMULA
MATHEMATICA
Select[Range[510], PrimeQ[(#^2-8)/8]&] (* Harvey P. Dale, Feb 03 2011 *)
PROG
(PARI) is(n)=isprime((n^2-8)/8) \\ Charles R Greathouse IV, Feb 20 2017
CROSSREFS
KEYWORD
nonn
AUTHOR
Pierre CAMI, Sep 12 2005
EXTENSIONS
Extended by Ray Chandler, Sep 15 2005
STATUS
approved