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A110443 Index k of the least colossally abundant number c=A004490(k) with sigma(c)/c >= n. 1

%I #7 Mar 30 2012 17:22:40

%S 2,5,9,14,19,27,40,56,82,119,180,275,426,673,1072,1728,2807,4596,7558,

%T 12497,20741,34544,57704,96638,162204,272802,459637,775678,1310959,

%U 2218651,3759507,6377858

%N Index k of the least colossally abundant number c=A004490(k) with sigma(c)/c >= n.

%C For the numbers, instead of the indices, see A110442. The last term, a(33), yields a 48361012-digit number having 6375908 prime factors.

%e a(4)=9 because the 9th colossally abundant number is c=55440 and sigma(c)/c = 4.18701 > 4, while the 8th colossally abundant number is c'=5040 and sigma(c')/c' = 3.838 < 4.

%K nonn

%O 2,1

%A _T. D. Noe_, Jul 20 2005

%E Definition and example clarified by Jonathan Sondow, Dec 08 2011

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Last modified April 25 07:07 EDT 2024. Contains 371964 sequences. (Running on oeis4.)