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a(1) = 10, a(n+1) = {a(n) followed by digit reversal(a(n))}/11.
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%I #7 Dec 05 2013 19:57:02

%S 10,91,829,75448,685898587,62354417071445326,

%T 566858337013139332941310642858666,

%U 51532576092103575721937331168969696987113273922657630119157623515

%N a(1) = 10, a(n+1) = {a(n) followed by digit reversal(a(n))}/11.

%C a(1) = 10 is chosen because for n = say d <=9, the sequence is trivially d,d,d,d,d,d,...

%C The next term has 129 digits (From Harvey P. Dale, Feb 20 2011 *)

%e a(2) = 1001/11=91, a(3) = 9119/11=829.

%t nxt[n_]:=Module[{idn=IntegerDigits[n]},FromDigits[Join[idn,Reverse[idn]]]/11]

%t NestList[nxt,10,8] (* _Harvey P. Dale_, Feb 20 2011 *)

%K base,easy,nonn

%O 1,1

%A _Amarnath Murthy_, Jul 30 2005

%E More terms from _Joshua Zucker_, May 10 2006