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a(1) = 3; a(n+1) = (a(n) + n)*(a(n) - n).
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%I #6 Sep 03 2017 03:31:14

%S 3,8,60,3591,12895265,166287859420200,27651652190552197880168039964,

%T 764613868867270163545228802175958319343780390069501121247,

%U 584634368464175013450777511329300527888604990906383317504017890900798292874089489710812952726292298514590194834945

%N a(1) = 3; a(n+1) = (a(n) + n)*(a(n) - n).

%p a[1]:=3: for n from 1 to 19 do a[n+1]:=(a[n]+n)*(a[n]-n) od: seq(a[n],n=1..9); # _Emeric Deutsch_, Jul 31 2005

%K easy,nonn

%O 1,1

%A _Amarnath Murthy_, Jul 25 2005

%E More terms from _Emeric Deutsch_, Jul 31 2005