OFFSET
0,3
COMMENTS
Diagonal sums of number triangle A110321.
FORMULA
a(n)=sum{k=0..floor(n/2), (n-k)!*J(n-2k+1)/k!}, J(n)=A001045(n).
MATHEMATICA
J[n_] := (2^n-(-1)^n)/3; a[n_] := Sum[(n-k)!*J[n-2*k+1]/k!, {k, 0, n/2}]; Table[a[n], {n, 0, 17}] (* Jean-François Alcover, Oct 08 2016 *)
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Jul 20 2005
STATUS
approved