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A110288 a(n) = 19*2^n. 6

%I #38 Jan 05 2023 03:12:03

%S 19,38,76,152,304,608,1216,2432,4864,9728,19456,38912,77824,155648,

%T 311296,622592,1245184,2490368,4980736,9961472,19922944,39845888,

%U 79691776,159383552,318767104,637534208,1275068416,2550136832,5100273664,10200547328,20401094656

%N a(n) = 19*2^n.

%C The first differences are the sequence itself. Doubling the terms gives the same sequence (beginning one step further).

%C 19 times powers of 2. - _Omar E. Pol_, Dec 17 2008

%H Vincenzo Librandi, <a href="/A110288/b110288.txt">Table of n, a(n) for n = 0..235</a>

%H Tanya Khovanova, <a href="http://www.tanyakhovanova.com/RecursiveSequences/RecursiveSequences.html">Recursive Sequences</a>

%H <a href="/index/Rec#order_01">Index entries for linear recurrences with constant coefficients</a>, signature (2).

%F G.f.: 19/(1-2*x). - _Philippe Deléham_, Nov 23 2008

%F a(n) = A000079(n)*19. - _Omar E. Pol_, Dec 17 2008

%F E.g.f.: 19*exp(2*x). - _G. C. Greubel_, Jan 04 2023

%t 19*2^Range[0, 60] (* _Vladimir Joseph Stephan Orlovsky_, Jun 09 2011 *)

%t NestList[2#&,19,30] (* _Harvey P. Dale_, May 11 2018 *)

%o (Magma) [19*2^n: n in [0..40]]; // _Vincenzo Librandi_, Apr 28 2011

%o (SageMath) [19*2^n for n in range(41)] # _G. C. Greubel_, Jan 04 2023

%Y Sequences of the form (2*m+1)*2^n: A000079 (m=0), A007283 (m=1), A020714 (m=2), A005009 (m=3), A005010 (m=4), A005015 (m=5), A005029 (m=6), A110286 (m=7), A110287 (m=8), this sequence (m=9), A175805 (m=10), A248646 (m=11), A164161 (m=12), A175806 (m=13), A257548 (m=15).

%K easy,nonn

%O 0,1

%A _Alexandre Wajnberg_, Sep 07 2005

%E Edited by _Omar E. Pol_, Dec 16 2008

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Last modified April 24 19:49 EDT 2024. Contains 371963 sequences. (Running on oeis4.)