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1,11

Table of n, a(n) for n=1..105.

a(25)=5 because 25 + 26 + 27 + 28 + 29 = 135 and 135/9 = 15, 5 consecutive

integers are needed.

Cf. A005349, A110029, A110031.

Sequence in context: A274514 A026181 A106601 * A211948 A021766 A286357

Adjacent sequences: A110027 A110028 A110029 * A110031 A110032 A110033

base,easy,nonn,changed

Jason Earls, Jul 08 2005

approved