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Table of n, a(n) for n=1..105.
a(25)=5 because 25 + 26 + 27 + 28 + 29 = 135 and 135/9 = 15, 5 consecutive
integers are needed.
Cf. A005349, A110029, A110031.
Sequence in context: A274514 A026181 A106601 * A211948 A021766 A286357
Adjacent sequences: A110027 A110028 A110029 * A110031 A110032 A110033
Jason Earls (zevi_35711(AT)yahoo.com), Jul 08 2005