%I #4 Dec 05 2013 19:57:00
%S 2,2,3,16,5,0,7,16,0,20,11,0,13,14,0,16,17,0,38,20,0,110,92,0,50,104,
%T 0,112,145,30,31,32,0,34,35,0,37,38,0,160,164,0,172,1100,0,92,188,0,
%U 98,50,0,104,106,0,110,112,0,754,118,0,305,124,0,128,130,0,134,136,0,70,71,0
%N Least multiple of n with digit reversal a prime, or 0 if no such multiple exists.
%C a(3k) = 0, k > 0.
%C A subsidiary sequence could be obtained by replacing a(3n) by the least multiple of n which on division by largest power of 3 that divides it gives a number whose digit reversal is prime.
%C Note also that a(77) = 0. - _Joshua Zucker_, May 04 2006
%K base,easy,nonn
%O 1,1
%A _Amarnath Murthy_, Jul 06 2005
%E More terms from _Joshua Zucker_, May 04 2006