OFFSET
0,4
COMMENTS
Since n^(2k+1) mod 4 = n^3 mod 4 for k>1 this sequence also represents n^5 mod 4; and n^7 mod 4; etc.
LINKS
FORMULA
a(n) = n^3 mod 4.
G.f. = (x+3*x^3)/(1-x^4).
a(n) = (n mod 2)*(n mod 4) = (1+(-1)^(n+1))*(2+i^(n+1))/2 with i=sqrt(-1). - Bruno Berselli, Mar 14 2011
PROG
(Sage) [power_mod(n, 3, 4 )for n in range(0, 105)] # Zerinvary Lajos, Oct 29 2009
(Magma) &cat[[0, 1, 0, 3]: k in [0..26]]; // Bruno Berselli, Mar 14 2011
(PARI) a(n)=n^3%4 \\ Charles R Greathouse IV, Apr 06 2016
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Bruce Corrigan (scentman(AT)myfamily.com), Aug 09 2005
STATUS
approved