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%I #3 Dec 05 2013 19:57:00
%S 1,1,121,123676641,123679391831145033529042881,
%T 123679391831147784436668492828330058796889905783980717429924756854206515936780161
%N a(1) = 1, a(n) = square of the concatenation of all previous terms.
%e a(3) = 11^2 = 121.
%K base,easy,nonn
%O 1,3
%A _Amarnath Murthy_, Aug 02 2005
%E More terms from Atilla Bora (borabanana(AT)gmail.com), Apr 23 2006