%N Numbers n such that the number of digits required to write the prime factors of n is equal to the number of divisors of n.
%C 190333 has 10 divisors and 10 digits in its prime factorization. What is the next term in this sequence with more divisors and digits?
%e 143 is a term because it takes 4 digits to write its prime factorization
%e 143=11*13 and has 4 divisors [1, 11, 13, 143].
%Y Cf. A076649.
%A Jason Earls (zevi_35711(AT)yahoo.com), Jul 13 2005