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A107972
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Triangle read by rows: T(n,k) = (k+1)(k+2)(n+2)(3n-2k+3)/12 for 0<=k<=n.
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1
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1, 3, 6, 6, 14, 20, 10, 25, 40, 50, 15, 39, 66, 90, 105, 21, 56, 98, 140, 175, 196, 28, 76, 136, 200, 260, 308, 336, 36, 99, 180, 270, 360, 441, 504, 540, 45, 125, 230, 350, 475, 595, 700, 780, 825, 55, 154, 286, 440, 605, 770, 924, 1056, 1155, 1210, 66, 186, 348
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OFFSET
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0,2
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COMMENTS
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Kekulé numbers for certain benzenoids. Column 0 yields the triangular numbers (A000217). Row sums yield A006414. T(n,n) = A002415(n+2).
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REFERENCES
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S. J. Cyvin and I. Gutman, Kekulé structures in benzenoid hydrocarbons, Lecture Notes in Chemistry, No. 46, Springer, New York, 1988 (p. 237; K{B(n,2,l)}).
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LINKS
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EXAMPLE
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Triangle begins:
1;
3,6;
6,14,20;
10,25,40,50;
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MAPLE
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T:=proc(n, k) if k<=n then (k+1)*(k+2)*(n+2)*(3*n-2*k+3)/12 else 0 fi end: for n from 0 to 10 do seq(T(n, k), k=0..n) od; # yields sequence in triangular form
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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