OFFSET
1,1
COMMENTS
a(n) = prime(n) for almost all n. Probably a(n) = prime(n) for all n > N for some N, but N must be very large. - Charles R Greathouse IV, Jul 20 2011
FORMULA
a(n) ~ n log n. - Charles R Greathouse IV, Jul 20 2011
MATHEMATICA
p=Prime[14]; b={p}; d=p; Do[Do[r=Prime[c]; If[FreeQ[b, r]&&Intersection@@IntegerDigits/@{d, r}=!={}, b=Append[b, r]; d=r; Break[]], {c, 1000}], {k, 60}]; b
CROSSREFS
Cf. A107353.
KEYWORD
nonn,base
AUTHOR
Zak Seidov and Eric Angelini, May 24 2005
STATUS
approved