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A107793
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Gaps in ones order in the tribonacci substitution of three symbols.
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0
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4, 5, 3, 5, 4, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 4, 5, 3, 5, 4, 5, 5, 4, 5, 3, 5, 4, 5, 3, 5, 4, 5, 5
(list; graph; refs; listen; history; internal format)
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OFFSET
| 0,1
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COMMENTS
| Average gap=N[Apply[Plus, b]/Length[b]]=4.38095
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FORMULA
| 1->(2), 2->{3}, 3->{1, 2, 3}, a(n) = orderones[n]-ordersones[n-1] gap in order of appearance of ones in the substitution
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MATHEMATICA
| s[1] = {2}; s[2] = {3};; s[3] = {1, 2, 3}; t[a_] := Flatten[s /@ a]; p[0] = {1}; p[1] = t[p[0]]; p[n_] := t[p[n - 1]] pp = p[13] a = Flatten[Table[If[pp[[j]] == 1, j, {}], {j, 1, Length[pp]}]] b = Table[a[[n]] - a[[n - 1]], {n, 2, Length[a]}]
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CROSSREFS
| Cf. A000045, A000213, A000931.
Sequence in context: A175725 A069197 A021692 * A196402 A004493 A170929
Adjacent sequences: A107790 A107791 A107792 * A107794 A107795 A107796
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KEYWORD
| nonn,uned
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AUTHOR
| Roger L. Bagula (rlbagulatftn(AT)yahoo.com), Jun 11 2005
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