1,2

Table of n, a(n) for n=1..59.

a(n) = SQRT(A106562(n)).

a(3)=17 because the third square which is not the sum of two primes (289=17^2) is the 17th one in the succession of the perfect squares (thus: index 17).

Cf. A106544-A106548, A106562-A106564, A106571, A106573-A106575, A106577.

Sequence in context: A184551 A190039 A066074 * A106574 A171125 A156781

Adjacent sequences: A106560 A106561 A106562 * A106564 A106565 A106566

nonn

Alexandre Wajnberg, May 09 2005

Extended by Ray Chandler, May 12 2005

approved