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A106233 An inverse Catalan transform of A003462. 3
0, 1, 3, 5, 5, 0, -14, -41, -81, -121, -121, 0, 364, 1093, 2187, 3281, 3281, 0, -9842, -29525, -59049, -88573, -88573, 0, 265720, 797161, 1594323, 2391485, 2391485, 0, -7174454, -21523361, -43046721, -64570081, -64570081 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,3

COMMENTS

The g.f. is obtained from that of A003462 through the mapping g(x)->g(x(1-x)). A003462 may be retrieved through the mapping g(x)->g(xc(x)), where c(x) is the g.f. of A000108. Binomial transform of x(1+x)/(1+x^2+x^4).

The sequence is identical to its sixth differences. See A140344(n). - Paul Curtz, Nov 09 2012

LINKS

Table of n, a(n) for n=0..34.

Index entries for linear recurrences with constant coefficients, signature (4,-7,6,-3).

FORMULA

G.f.: x(1-x)/((1-x+x^2)*(1-3*x+3*x^2)); a(n)=sum{k=0..floor(n/2), C(n-k, k)(-1)^k(3^(n-k)-1)/2}.

a(n)=Sum_{k, 0<=k<=n} A109466(n,k)*A003462(k). [From Philippe Deléham, Oct 30 2008]

a(n) = (1/2)*[A057083(n) - [1,1,0,0,-1,-1]_6 ]. -- Ralf Stephan, Nov 15 2010.

a(n) = 4*a(n-1)-7*a(n-2)+6*a(n-3)-3*a(n-4) = A140343(n+2)-A140343(n+1). - Paul Curtz, Nov 09 2012

a(n) is the binomial transform of the sequence 0, 1, 1, -1, -1, 0,... = A103368(n+5). - Paul Curtz, Nov 09 2012

EXAMPLE

The sequence and its higher order differences (periodic after 6 rows):

0,  1,  3,  5,  5,   0, -14,...

1,   2,  2,  0, -5, -14, -27,...

1,   0, -2, -5, -9, -13, -13,...

-1, -2, -3, -4, -4,   0,  13,...      = -A134581(n+1)

-1, -1, -1,  0,  4,  13,  27,...

0,   0,  1,  4,  9,  14,  14,...      = A140343(n+2)

0,   1,  3,  5,  5,   0, -14,... . -  Paul Curtz, Nov 09 2912

CROSSREFS

Cf. A103368.

Sequence in context: A152416 A200334 A138112 * A198492 A077860 A261340

Adjacent sequences:  A106230 A106231 A106232 * A106234 A106235 A106236

KEYWORD

easy,sign

AUTHOR

Paul Barry, Apr 26 2005

STATUS

approved

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Last modified October 15 11:25 EDT 2018. Contains 316224 sequences. (Running on oeis4.)