|
| |
|
|
A106038
|
|
Triangle Loop von Koch substitution: characteristic polynomial:x^3-6x^2+8*x.
|
|
0
| |
|
|
1, 2, 3, 1, 2, 1, 1, 2, 3, 1, 1, 3, 1, 2, 3, 1, 2, 1, 1, 2, 1, 2, 3, 1, 1, 2, 3, 1, 2, 1, 1, 2, 3, 1, 1, 3, 1, 2, 3, 1, 1, 2, 3, 1, 3, 1, 1, 3, 1, 2, 3, 1, 2, 1, 1, 2, 3, 1, 1, 3, 1, 2, 3, 1, 2, 1, 1, 2, 1, 2, 3, 1, 1, 2, 3, 1, 2, 1, 1, 2, 1, 2, 3, 1, 2, 1, 1, 2, 3, 1, 1, 3, 1, 2, 3, 1, 1, 2, 3, 1, 2, 1, 1, 2, 3
(list; graph; refs; listen; history; internal format)
|
|
|
|
OFFSET
| 0,2
|
|
|
COMMENTS
| To get the fractal: bb = aa /. 1 -> {1, 0} /. 2 -> {-1, N[Sqrt[3]]}/2 /. 3 -> {-1, -N[Sqrt[3]]}/2; ListPlot[FoldList[Plus, {0, 0}, bb], PlotJoined -> True, PlotRange -> All, Axes -> False];
|
|
|
FORMULA
| 1->{1, 2, 3, 1}, 2->{2, 1, 1, 2}, 3->{3, 1, 1, 3}
|
|
|
MATHEMATICA
| s[1] = {1, 2, 3, 1}; s[2] = {2, 1, 1, 2}; s[3] = {3, 1, 1, 3};; t[a_] := Flatten[s /@ a]; p[0] = {1}; p[1] = t[p[0]]; p[n_] := t[p[n - 1]] aa = p[4]
|
|
|
CROSSREFS
| Sequence in context: A064529 A091654 A127246 * A078711 A076423 A075660
Adjacent sequences: A106035 A106036 A106037 * A106039 A106040 A106041
|
|
|
KEYWORD
| nonn,uned
|
|
|
AUTHOR
| Roger Bagula (rlbagulatftn(AT)yahoo.com), May 05 2005
|
| |
|
|
