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%I #4 Mar 30 2012 17:34:15
%S 1,1,2,3,4,5,1,2,3,4,5,2,3,4,5,1,3,4,6,1,2,4,7,1,2,3,8,1,6,7,8,1,2,3,
%T 4,5,2,3,4,5,1,3,4,6,1,2,4,7,1,2,3,8,1,6,7,8,2,3,4,5,1,3,4,6,1,2,4,7,
%U 1,2,3,8,1,6,7,8,1,3,4,6,1,2,4,7,1,2,3,8,1,6,7,8,2,3,4,5,1,2,4,7,1,2,3,8,2
%N An eight-symbol substitution on an hypertetrahedron with four symbol connection per vertex.
%C This flow can be visualized in 3d by using a cube's vertices as the substitution for the eight points.
%F 1->{2, 3, 4, 5}, 2->{1, 3, 4, 6}, 3->{1, 2, 4, 7}, 4->{1, 2, 3, 8}, 5->{1, 6, 7, 8}, 6->{2, 5, 7, 8}, 7->{3, 5, 6, 8}, 8->{4, 5, 6, 7}
%t s[1]={2, 3, 4, 5}; s[2]={1, 3, 4, 6}; s[3]={1, 2, 4, 7};s[4]={1, 2, 3, 8}; s[5]={1, 6, 7, 8}; s[6]={2, 5, 7, 8}; s[7]={3, 5, 6, 8};s[8]={4, 5, 6, 7}; t[a_] := Join[a, Flatten[s/@a]]; p[0]={1};p[1]=t[{1}]; p[n_]:=t[p[n-1]] a=Flatten[Table[p[n], {n, 0, 3}]]
%K nonn,uned
%O 0,3
%A _Roger L. Bagula_, Apr 26 2005
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