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A105932
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An eight-symbol substitution on an hypertetrahedron with four symbol connection per vertex.
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1
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1, 1, 2, 3, 4, 5, 1, 2, 3, 4, 5, 2, 3, 4, 5, 1, 3, 4, 6, 1, 2, 4, 7, 1, 2, 3, 8, 1, 6, 7, 8, 1, 2, 3, 4, 5, 2, 3, 4, 5, 1, 3, 4, 6, 1, 2, 4, 7, 1, 2, 3, 8, 1, 6, 7, 8, 2, 3, 4, 5, 1, 3, 4, 6, 1, 2, 4, 7, 1, 2, 3, 8, 1, 6, 7, 8, 1, 3, 4, 6, 1, 2, 4, 7, 1, 2, 3, 8, 1, 6, 7, 8, 2, 3, 4, 5, 1, 2, 4, 7, 1, 2, 3, 8, 2
(list; graph; refs; listen; history; internal format)
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OFFSET
| 0,3
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COMMENTS
| This flow can be visualized in 3d by using a cube's vertices as the substitution for the eight points.
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FORMULA
| 1->{2, 3, 4, 5}, 2->{1, 3, 4, 6}, 3->{1, 2, 4, 7}, 4->{1, 2, 3, 8}, 5->{1, 6, 7, 8}, 6->{2, 5, 7, 8}, 7->{3, 5, 6, 8}, 8->{4, 5, 6, 7}
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MATHEMATICA
| s[1]={2, 3, 4, 5}; s[2]={1, 3, 4, 6}; s[3]={1, 2, 4, 7}; s[4]={1, 2, 3, 8}; s[5]={1, 6, 7, 8}; s[6]={2, 5, 7, 8}; s[7]={3, 5, 6, 8}; s[8]={4, 5, 6, 7}; t[a_] := Join[a, Flatten[s/@a]]; p[0]={1}; p[1]=t[{1}]; p[n_]:=t[p[n-1]] a=Flatten[Table[p[n], {n, 0, 3}]]
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CROSSREFS
| Sequence in context: A190595 A053841 A010884 * A106652 A193106 A053827
Adjacent sequences: A105929 A105930 A105931 * A105933 A105934 A105935
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KEYWORD
| nonn,uned
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AUTHOR
| Roger L. Bagula (rlbagulatftn(AT)yahoo.com), Apr 26 2005
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