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A105555
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Let d = number of divisors of n; a(n) = d-th prime.
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2
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2, 3, 3, 5, 3, 7, 3, 7, 5, 7, 3, 13, 3, 7, 7, 11, 3, 13, 3, 13, 7, 7, 3, 19, 5, 7, 7, 13, 3, 19, 3, 13, 7, 7, 7, 23, 3, 7, 7, 19, 3, 19, 3, 13, 13, 7, 3, 29, 5, 13, 7, 13, 3, 19, 7, 19, 7, 7, 3, 37, 3, 7, 13, 17, 7, 19, 3, 13, 7, 19, 3, 37, 3, 7, 13, 13, 7, 19, 3, 29, 11, 7, 3, 37, 7, 7, 7, 19, 3
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OFFSET
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1,1
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LINKS
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FORMULA
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EXAMPLE
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n = 6 has 4 divisors, prime(4) = 7, so a(6) = 7.
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MATHEMATICA
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PROG
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(PARI) d(n) = for(x=1, n, print1(prime(numdiv(x))", "))
(Python)
from sympy import prime, divisor_count
def a(n): return prime(divisor_count(n)) # Indranil Ghosh, May 25 2017
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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