A105175 Define a(1)=0,a(2)=0,a(3)=9235919,a(4)=14984879 then a(n)=(a(3)+a(4)+1)*(2*a(n-2)+1)-a(n-3)-1. These numbers are such that 71*(a(n)^2)+71*a(n)+1 = j^2 = a square.

0, 0, 9235919, 14984879, 447402699579360, 725891508817440, 21672901717138141202159