|
| |
|
|
A105113
|
|
Triangle read by rows, based on the morphism f: 1->2, 2->3, 3->{3,5,5,5,4}, 4->5, 5->6, 6->{6,2,2,2,1}. First row is 1. If current row is a,b,c,..., then the next row is a,b,c,...,f(a),f(b),f(c),...
|
|
0
| |
|
|
1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 3, 5, 5, 5, 4, 1, 2, 2, 3, 2, 3, 3, 3, 5, 5, 5, 4, 2, 3, 3, 3, 5, 5, 5, 4, 3, 3, 5, 5, 5, 4, 3, 5, 5, 5, 4, 3, 5, 5, 5, 4, 6, 6, 6, 5, 1, 2, 2, 3, 2, 3, 3, 3, 5, 5, 5, 4, 2, 3, 3, 3, 5, 5, 5, 4, 3, 3, 5, 5, 5, 4, 3, 5, 5, 5, 4, 3, 5, 5, 5, 4, 6, 6, 6, 5, 2, 3, 3, 3, 5, 5
(list; graph; refs; listen; history; internal format)
|
|
|
|
OFFSET
| 0,3
|
|
|
COMMENTS
| This substitution with the polynomial that goes with it gives a new tile, not predicted in the Kenyon paper.
q=3 version of bi-Kenyon 6-symbol substitution.
|
|
|
LINKS
| Richard Kenyon, The Construction of Self-Similar Tilings
|
|
|
MATHEMATICA
| s[n_] := n /. {1 -> 2, 2 -> 3, 3 -> {3, 5, 5, 5, 4}, 4 -> 5, 5 -> 6, 6 -> {6, 2, 2, 2, 1}}; t[a_] := Join[a, Flatten[s /@ a]] p[0] = {1}; p[1] = t[{1}]; Flatten[ NestList[t, {1}, 5]]
|
|
|
CROSSREFS
| Cf. A103684, A105112, A105111.
Sequence in context: A104231 A105111 A105112 * A105056 A105061 A105164
Adjacent sequences: A105110 A105111 A105112 * A105114 A105115 A105116
|
|
|
KEYWORD
| nonn,tabf
|
|
|
AUTHOR
| Roger Bagula (rlbagulatftn(AT)yahoo.com), Apr 07 2005
|
| |
|
|
