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A bi-Minimal Pisot substitution.
0

%I #4 Mar 12 2014 16:36:46

%S 1,1,2,1,2,2,3,1,2,2,3,2,3,3,5,4,1,2,2,3,2,3,3,5,4,2,3,3,5,4,3,5,4,5,

%T 4,6,5,1,2,2,3,2,3,3,5,4,2,3,3,5,4,3,5,4,5,4,6,5,2,3,3,5,4,3,5,4,5,4,

%U 6,5,3,5,4,5,4,6,5,5,4,6,5,6,5,2,1,6,1,2,2,3,2,3,3,5,4,2,3,3,5,4,3,5,4,5,4

%N A bi-Minimal Pisot substitution.

%F 1-> 2 2->3 3->{5, 4} 4->5 5->6 6->{2, 1}

%t s[1] = {2}; s[2] = {3}; s[3] = {5, 4}; s[4] = {5}; s[5] = {6}; s[6] = {2, 1}; t[a_] := Join[a, Flatten[s /@ a]]; p[0] = {1}; p[1] = t[{1}]; p[n_] := t[p[n - 1]] aa = Flatten[Table[p[n], {n, 0, 6}]]

%Y Cf. A073058.

%K nonn,uned

%O 0,3

%A _Roger L. Bagula_, Apr 07 2005