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%I
%S 1,2,3,2,4,4,2,2,4,3,3,4,5,5,5,5,5,2,2,4,3,3,6,3,6,4,3,5,6,6,5,8,5,6,
%T 3,6,4,6,2,3,5,8,3,3,2,4,5,4,5,3,6,6,5,7,4,7,4,4,2,8
%N Number of distinct prime divisors of 1000^n - 3 where n = 1,2,3,....
%e If n=1, then 1000^n - 3 = 1000^1 - 3 = 997 which is a prime, so the first term is 1.
%Y Cf. A105069, A105068.
%K nonn
%O 1,2
%A _Parthasarathy Nambi_, Apr 06 2005
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