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A103823
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Table of "maximum oddness" operation.
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2
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0, 1, 1, 2, 1, 2, 3, 1, 1, 3, 4, 3, 2, 3, 4, 5, 1, 3, 3, 1, 5, 6, 5, 2, 3, 2, 5, 6, 7, 1, 5, 3, 3, 5, 1, 7, 8, 7, 6, 3, 4, 3, 6, 7, 8, 9, 1, 7, 3, 5, 5, 3, 7, 1, 9, 10, 9, 2, 7, 6, 5, 6, 7, 2, 9, 10, 11, 1, 9, 3, 7, 5, 5, 7, 3, 9, 1, 11, 12, 11, 10, 3, 4, 7, 6, 7, 4, 3, 10, 11, 12, 13, 1, 11, 3, 9, 5, 7, 7, 5
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OFFSET
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0,4
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COMMENTS
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T(i,j) is whichever of i,j has the 1 in the rightmost differing bit of their binary representations. Defines a complete ordering of the integers: all odd numbers are "more odd" than all even numbers, for numbers of same parity remaining bits are recursively compared to determine ordering.
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LINKS
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FORMULA
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T(i, j) = max(Ri, Rj), where Rn is the reflection of n at the "binary point".
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EXAMPLE
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T(11,13)=11, since the rightmost differing bit position is 1 for 11=1011 binary and 0 for 13=1101 binary.
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PROG
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(PARI) T(n, k) = { if (n==k, return (n), for (i=0, oo, my (nn=bittest(n, i), kk=bittest(k, i)); if (nn && !kk, return (n), kk && !nn, return (k)))) } \\ Rémy Sigrist, Feb 08 2020
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CROSSREFS
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Cf. A103822 (the complementary operation).
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KEYWORD
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AUTHOR
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STATUS
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approved
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