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a(1) = 1, a(n) = product of n successive numbers starting with a(n-1) + 1.
1

%I #6 Aug 23 2014 11:13:14

%S 1,6,504,65813284680,

%T 1234718152224069224489356305213161520251951242625962440

%N a(1) = 1, a(n) = product of n successive numbers starting with a(n-1) + 1.

%C a(6) has 325 digits and a(7) has 2272 digits. - _Harvey P. Dale_, Aug 23 2014

%F a(n+1) = !{a(n)+n +1}/!{a(n)}

%e a(2) = 2*3 = 6, a(3) = 7*8*9 = 504.

%t nxt[{n_,a_}]:={n+1,Times@@Range[a+1,a+1+n]}; Transpose[NestList[nxt,{1,1},5]][[2]] (* _Harvey P. Dale_, Aug 23 2014 *)

%Y Cf. A103519.

%K easy,nonn

%O 1,2

%A _Amarnath Murthy_, Feb 10 2005

%E More terms from _Olaf Voß_, Feb 26 2005. (The next term is too large to include.)