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A103448
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a(n) = Sum_{k=0..n} Moebius(binomial(n,k)).
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3
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1, 2, 1, 0, 3, 2, 6, 4, 1, 2, 6, 4, 0, -6, 8, 6, 2, -2, 2, -4, 4, 10, 4, 8, 0, 4, 8, 2, 4, 0, -2, -4, 2, 4, 0, 4, 2, -4, 10, 4, 0, -8, 6, -2, 4, -4, 8, 2, 2, 2, 2, 4, 6, 2, 0, 6, 2, 2, 2, -6, 0, 6, 4, 8, 2, 4, 2, 0, 0, 8, -4, -2, 2, 4, 2, 0, -2, 14, 10, -2, 2, 2, 4, 2, 4, -2, 0, 8, 4, 2, 2, -2, 6, 0, -6, 14, 2, 0, 2, 2, 2, 4, 0, 2, -2
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OFFSET
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0,2
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COMMENTS
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LINKS
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FORMULA
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a(n) = Sum_{k=0..n} Moebius(binomial(n,k)).
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EXAMPLE
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a(4)=3 because mu(1) + mu(4) + mu(6) + mu(4) + mu(1) = 1 + 0 + 1 + 0 + 1 = 3.
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MATHEMATICA
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Table[Sum[MoebiusMu[Binomial[n, k]], {k, 0, n}], {n, 0, 120}] (* G. C. Greubel, Jun 16 2021 *)
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PROG
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(Magma) [(&+[ MoebiusMu(Binomial(n, k)): k in [0..n]]): n in [0..120]]; // G. C. Greubel, Jun 16 2021
(Sage) [sum(moebius(binomial(n, k)) for k in (0..n)) for n in (0..120)] # G. C. Greubel, Jun 16 2021
(PARI) a(n) = sum(k=0, n, moebius(binomial(n, k))); \\ Michel Marcus, Jun 17 2021
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CROSSREFS
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KEYWORD
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sign
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AUTHOR
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STATUS
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approved
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