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Numbers k such that sigma(2^k-1) >= 2*(2^k-1)-1, i.e., the number 2^k-1 is perfect, abundant, or least deficient.
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%I #10 Aug 24 2021 06:27:49

%S 1,12,24,36,40,48,60,72,80,84,90,96,108,120,132,140,144,156,160,168,

%T 180,192,200,204,210,216,220,228,240,252,264,270,276,280,288,300,312,

%U 320,324,330,336,348,360,372,384,396,400,408,420,432,440,444,450,456,468

%N Numbers k such that sigma(2^k-1) >= 2*(2^k-1)-1, i.e., the number 2^k-1 is perfect, abundant, or least deficient.

%C Is there an odd term besides 1? Numbers 2^a(i)-1 form set difference of sequences A103289 and A096399.

%C Odd terms > 1 exist, but there are none < 10^7. If k > 1 is an odd term, then 2^k-1 must have more than 900000 distinct prime factors and all of them must be members of A014663. - _David Wasserman_, Apr 15 2008

%F Numbers k such that 2^k-1 is in A103288.

%o (PARI) for(i=1,1000,n=2^i-1;if(sigma(n)>=2*n-1,print(i)));

%Y Cf. A103288, A103289, A103292, A023196.

%K hard,nonn

%O 1,2

%A _Max Alekseyev_, Jan 28 2005

%E More terms from _David Wasserman_, Apr 15 2008