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A102515
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a(n) = floor(1 + sqrt(2n + 1)).
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0
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2, 2, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 9, 9, 9, 9, 9, 9, 9, 9, 10, 10, 10, 10, 10, 10, 10, 10, 10, 10, 11, 11, 11, 11, 11, 11, 11, 11, 11, 11, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 12, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13, 13
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OFFSET
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0,1
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COMMENTS
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The first occurrence of k appears at floor((k-1)^2/2), beginning with k=3. - Robert G. Wilson v, Mar 01 2015
If the sign inside the sqrt() is changed from "+" to "-", then the offset must be changed from 0 to 1 in order for the terms in the data to remain the same. - Robert G. Wilson v, Mar 01 2015
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LINKS
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FORMULA
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MATHEMATICA
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Table[Floor[1+Sqrt[2n+1]], {n, 0, 100}] (* Harvey P. Dale, Feb 28 2015 *)
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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