1,1

Conjecture: a(n) = 2^n for n>5. - Ray Chandler Feb 25 2005

Table of n, a(n) for n=1..31.

a(1) = 2;

a(2) = 9 = 3*3 = 2+7;

a(3) = 12 = 2*2*3 = 2+3+7;

a(4) = 36 = 2*2*3*3 = 3+5+11+17;

a(5) = 48 = 2*2*2*2*3 = 2+3+5+7+31.

Sequence in context: A178312 A253608 A126977 * A324571 A076505 A218073

Adjacent sequences: A102234 A102235 A102236 * A102238 A102239 A102240

nonn

Giovanni Teofilatto, Feb 18 2005

Corrected and extended by Ray Chandler Feb 25 2005

approved