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Remove the least number of commas from A093086 and concatenate digits so as to always have a(n) < a(n+1).
3

%I #16 May 17 2021 22:11:39

%S 0,1,12,35,81,394,1213,5334,8867,12161,41383,377554,1111610,1412109,

%T 5222771,15533191,47449148,261086410,1051111813,1051210871,8141051115,

%U 62229944156,331815899551,562261184411,1813856119649,9613171814106,61184872912852,299411131172101

%N Remove the least number of commas from A093086 and concatenate digits so as to always have a(n) < a(n+1).

%C The zeros at the first digits of a term are omitted. 35th term was such a number (01152299487468610171) so it is written without the zero in the first digit. - _Hakan Icoz_, Sep 03 2020

%H Hakan Icoz, <a href="/A102085/b102085.txt">Table of n, a(n) for n = 0..2000</a>

%e a(4) = 81, the next term must be bigger than the previous term with least commas removed.

%e 81 < 3 is not true; 81 < 39 is not true; 81 < 394 = a(5) is the next term since it satisfies a(n) < a(n+1).

%Y Cf. A093086.

%K base,easy,nonn

%O 0,3

%A _Eric Angelini_, Feb 13 2005

%E More terms from _Hakan Icoz_, Sep 03 2020