OFFSET
0,4
COMMENTS
There are two maximum values when n is of the form k^2 + 2k - 1 (i.e., 2 less than a square, A008865 offset) in which case m = k +/- 1. In general m is the integer with the same parity as n closest to sqrt(n+2) - 1.
The largest difference between adjacent binomial coefficients on n-th row of Pascal's triangle. - Vladimir Reshetnikov, Sep 16 2019
LINKS
Reinhard Zumkeller, Table of n, a(n) for n = 0..1000
FORMULA
a(n) = (m+1)*binomial(n+1, (n-m)/2)/(n+1) where m = floor(sqrt(n+2) - (1 + (-1)^floor(n + sqrt(n+2) - 1))/2). a(n) seems to be slightly less than 2^n/n.
PROG
(Haskell)
a101461 = maximum . a053121_row -- Reinhard Zumkeller, Mar 04 2012
CROSSREFS
KEYWORD
nonn
AUTHOR
Henry Bottomley, Jan 20 2005
STATUS
approved