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A101371
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Triangle read by rows: T(n,k) is the number of noncrossing trees with n edges and k leaves at level 1.
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2
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1, 0, 1, 2, 0, 1, 7, 4, 0, 1, 34, 14, 6, 0, 1, 171, 72, 21, 8, 0, 1, 905, 370, 114, 28, 10, 0, 1, 4952, 1995, 597, 160, 35, 12, 0, 1, 27802, 11064, 3278, 852, 210, 42, 14, 0, 1, 159254, 62774, 18420, 4762, 1135, 264, 49, 16, 0, 1, 927081, 362614, 105618, 27104, 6455, 1446, 322, 56, 18, 0, 1
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OFFSET
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0,4
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COMMENTS
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LINKS
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FORMULA
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T(n, k) = Sum_{i=0..n-k} (-1)^i*((k+i+1)/(2n-k-i+1)) binomial(k+i, i) binomial(3n-2k-2i, n-k-i) for 0 <= k <= n.
G.f.: g/(1+z*g-t*z*g), where g = 1+z*g^3.
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EXAMPLE
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Triangle begins:
1;
0, 1;
2, 0, 1;
7, 4, 0, 1;
34, 14, 6, 0, 1;
171, 72, 21, 8, 0, 1;
...
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MAPLE
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T:=proc(n, k) if k<=n then sum((-1)^i*(k+i+1)*binomial(k+i, i)*binomial(3*n-2*k-2*i, n-k-i)/(2*n-k-i+1), i=0..n-k) else 0 fi end: for n from 0 to 10 do seq(T(n, k), k=0..n) od; # yields sequence in triangular form
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MATHEMATICA
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t[n_, k_] := Sum[(-1)^i*(k + i + 1)/(2n - k - i + 1)*Binomial[k + i, i]* Binomial[3n - 2k - 2i, n - k - i], {i, 0, n - k}]; Table[t[n, k], {n, 0, 10}, {k, 0, n}] // Flatten (* Jean-François Alcover, Jan 21 2013, after Maple *)
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PROG
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(PARI) T(n, k) = sum(i=0, n-k, (-1)^i*(k+i+1)*binomial(k+i, i)*binomial(3*n-2*k-2*i, n-k-i)/(2*n-k-i+1)); \\ Andrew Howroyd, Nov 06 2017
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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