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A101341
Fibonacci-Fermat numbers.
0
2, 5, 1597, 229265413057075367692743352179590077832064383222590237
OFFSET
0,1
COMMENTS
a(4) = 1184388169...3238828317 has 13697 decimal digits. - Alois P. Heinz, Aug 30 2024
FORMULA
a(n) = Fibonacci(2^(2^n)+1) = A000045(A000215(n)).
PROG
(PARI) a(n)=fibonacci(2^(2^n)+1)
CROSSREFS
Sequence in context: A051131 A306785 A119748 * A079014 A215436 A082973
KEYWORD
nonn
AUTHOR
Jorge Coveiro, Dec 24 2004
STATUS
approved